| Author |
Message |
js5895
Guest
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 Posted:
Thu Mar 24, 2005 1:10 am Post subject:
Find current from voltage drop? |
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Hi,
The voltage drop formula:
K x I x L x 2
E = ----------------
CMA
I know all the values, except "I", so is there a formula to find "I".
Thanks.
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Gareth
Guest
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| Posted:
Thu Mar 24, 2005 1:10 am Post subject:
Re: Find current from voltage drop? |
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js5895 wrote:
| Quote: | Hi,
The voltage drop formula:
K x I x L x 2
E = ----------------
CMA
I know all the values, except "I", so is there a formula to find "I".
|
Are you saying that you know all the values in your equation except I,
and you want to find I? If so that is simple algebra.
Multiply both sides of the equation by CMA:-
E x CMA = K x I x L x 2
Then divide both sides by K x L x 2:-
E x CMA
---------- = I
K x L x 2
--
-----------------------------------------------------------------------
To reply to me directly:
Replace privacy.net with: totalise DOT co DOT uk and replace me with
gareth.harris |
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Kitchen Man
Guest
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| Posted:
Thu Mar 24, 2005 1:10 am Post subject:
Re: Find current from voltage drop? |
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On Wed, 23 Mar 2005 20:38:00 GMT in sci.electronics.basics, "js5895"
<js5895@tmp.com> wrote msg <Isk0e.152358$nC5.4171@twister.nyroc.rr.com>:
| Quote: | Hi,
The voltage drop formula:
K x I x L x 2
E = ----------------
CMA
I know all the values, except "I", so is there a formula to find "I".
|
See Gareth's answer, unless you don't know either E or I, in which case
you cannot find the answer from the known information.
I have a question. What are K, C, M and A? I'm assuming this is a
formula for the drop across an inductor, where E = I * XL, and XL =
2*Pi*f*L, so somehow Pi*f = K/(CMA)? Thanks.
--
Al Brennan
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John Larkin
Guest
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| Posted:
Thu Mar 24, 2005 1:10 am Post subject:
Re: Find current from voltage drop? |
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On Wed, 23 Mar 2005 16:19:09 -0700, Kitchen Man <nannerbac@yahoo.com>
wrote:
| Quote: | On Wed, 23 Mar 2005 20:38:00 GMT in sci.electronics.basics, "js5895"
js5895@tmp.com> wrote msg <Isk0e.152358$nC5.4171@twister.nyroc.rr.com>:
Hi,
The voltage drop formula:
K x I x L x 2
E = ----------------
CMA
I know all the values, except "I", so is there a formula to find "I".
See Gareth's answer, unless you don't know either E or I, in which case
you cannot find the answer from the known information.
I have a question. What are K, C, M and A? I'm assuming this is a
formula for the drop across an inductor, where E = I * XL, and XL =
2*Pi*f*L, so somehow Pi*f = K/(CMA)? Thanks.
|
Probably wire loss E in volts.
L = length
I = current
CMA = wire cross-sectional area, circular mils
K = fudge factor
2 = round trip
John |
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js5895
Guest
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| Posted:
Thu Mar 24, 2005 7:10 am Post subject:
Re: Find current from voltage drop? |
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Thank You very much.
If thats simple algebra, I don't know algebra, lol.
K = Approximate/Exact K of wire
I = Current
L = Length of wire, one way
2 = There and back
E = Voltage drop
CMA = Circular Mill Area of wire
"John Larkin" <jjlarkin@highNOTlandTHIStechnologyPART.com> wrote in message
news:efv341ppncqc4bgbocfju75m9rqd2k7bp2@4ax.com...
| Quote: | On Wed, 23 Mar 2005 16:19:09 -0700, Kitchen Man <nannerbac@yahoo.com
wrote:
On Wed, 23 Mar 2005 20:38:00 GMT in sci.electronics.basics, "js5895"
js5895@tmp.com> wrote msg <Isk0e.152358$nC5.4171@twister.nyroc.rr.com>:
Hi,
The voltage drop formula:
K x I x L x 2
E = ----------------
CMA
I know all the values, except "I", so is there a formula to find "I".
See Gareth's answer, unless you don't know either E or I, in which case
you cannot find the answer from the known information.
I have a question. What are K, C, M and A? I'm assuming this is a
formula for the drop across an inductor, where E = I * XL, and XL =
2*Pi*f*L, so somehow Pi*f = K/(CMA)? Thanks.
Probably wire loss E in volts.
L = length
I = current
CMA = wire cross-sectional area, circular mils
K = fudge factor
2 = round trip
John
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