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jason
Guest
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Posted:
Mon Mar 21, 2005 6:10 am Post subject:
Q Factor |
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Hello All
Say Impedance Z i = jwL + Rs
(Rs is in series and it is actually the internal series resistance,
this means inductor is an ideal one)
So if we assume this way, then does it mean jwL comes from the ideal
inductor? Not from any of the Rs at all?
If we want to find Q of the inductor
we will use Q= wL/Rs where SL(or jwL) is not involved totally in the Q
equation.
Am I right ?
Kindly enlighthen
Thank you
Jason
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John - KD5YI
Guest
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Posted:
Mon Mar 21, 2005 11:59 pm Post subject:
Re: Q Factor |
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jason wrote:
Hi, Jason -
| Quote: | Say Impedance Z i = jwL + Rs
(Rs is in series and it is actually the internal series resistance,
this means inductor is an ideal one)
So if we assume this way, then does it mean jwL comes from the ideal
inductor? Not from any of the Rs at all?
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That is correct.
| Quote: | If we want to find Q of the inductor
we will use Q= wL/Rs where SL(or jwL) is not involved totally in the Q
equation.
Am I right ?
|
You do not need S or j, so the relation is Q = wL/R.
| Quote: | Kindly enlighthen
Thank you
Jason
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John |
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jason
Guest
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Posted:
Wed Mar 23, 2005 6:10 am Post subject:
Re: Q Factor |
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Thank you John
You have been very helpful
Also I am lucky that no one sabotaged this enquiry
Cheers
Jason
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jason
Guest
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Posted:
Wed Mar 23, 2005 6:10 am Post subject:
Re: Q Factor |
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Thank you John
You have been very helpful
Also I am lucky that no one sabotaged this enquiry
Cheers
Jason |
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