Brent
Joined: 06 Jul 2007
Posts: 1
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 Posted:
Sat Jul 07, 2007 12:30 am Post subject:
2 voltage sources and a ground |
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2V ---1K----()----1K---- 6v
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75K
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Let's say you have two voltage sources, 2v and 6v, and a ground all connected to one common node. On the 2v and 6v branches there is a 1k resistor, and on the ground branch there is a 75k resistor. My circuit simulation program tells me the current on the 2v branch is 1.974mA, the current on the 6v branch 2.027mA, and the current on the ground branch is 52.847uA. This seems fair, since 1.974mA and 52.847uA add up to 2.027mA, so current into the node equals the current out. The voltage at the common node is 3.974v and that seems to satisfy ohm's law for all 3 branches. My question is how is the 3 branch currents calculated? Thank you for your time. It is much appreciated.
-Brent
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