Electronics

scotthr · Joined: 02 Dec 2006 Posts: 6

Voltage Divider Example;
R1 R2
V+ o-------------/\/\/\/\/\--------0-------------/\/\/\/\/\------------o V-
t1 t2 t3

R1 & R2 = 10K ohm
t1, t2, t3 = tap points
V = +5vdc

According to my math and the examples I have read about, placing a volt meters negitive probe to t3 and the volt meters positive probe to t1 I should get 5vdc right?

If I put the negitive probe to t3 and the positive probe to t2 then I should
get 2.5 vdc right?

ok, well then how does this differ from using an opamp to boost the output of a sensor?

I thought I had it, then this....

neon · Joined: 25 Feb 2006 Posts: 570

Passive and Active is the difference. as long as you never change the setup it will remain so. There can never be a gain of any sort from this setup divider.You don't seem to grasp the electronic notetion. if you say 5v it means 5 volts from gnd and it is a ref. point gnd can be pos. or neg. by looking at your divider i see -v to me and everybody else it say neg volts omission of a sign means +
5v +res->+res-> and so on.the + and - notetion indicate positive current flow or electron flow as opposed to hole flow whereby it will be a reversal of flow indication. If you are confused don't worry you have plenty of company.

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